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How many of you can genuinely solve this?
ebQEDN
No.156459
Anyone who is 12th pass in science stream should be able to solve this.
obQWXh
No.156461
>>156459(OP)
Ban this nanhajeet. Mods!!!!!!
ebQEDN
No.156462
>inb4 AI chamars and jewgle bhangis
Don't
Fuck off
J8h/bb
No.156463
no, i cant,
ebQEDN
No.156465
>>156463
Atleast try yaar, what comes to your mind?
DJ0fdi
No.156469
Maximize
(46-x)156* 6x?
DJ0fdi
No.156470
>>156469
*40-x
xXwe1a
No.156471
>>156469
(40-x)(156+6x) chamar
ebQEDN
No.156472
>>156469
It will be (156 + 6x)(40 - x) saars.
per chair price me 6 ke multiples add honge multiply thode hi honge.
DJ0fdi
No.156474
4rWRjk
No.156483
>>156459(OP)
>application of derivatives question
Yaar heendu…. Kabsy tumhary pas akal ayegy khi khi khi…
ebQEDN
No.156487
Do you guys remember we used to have Math Chad threads of old inch?
I miss Bhangali anon.
ebQEDN
No.156494
p0LbZj
No.156499
>>156494
how???
d8ql62
No.156505
>>156499
Let some other anons try yaar
4rWRjk
No.156515
>>156494
5:4?
VAoSnE
No.156518
>>156515
right saar
4rWRjk
No.156521
>>156518
Not so difficult sirs, gubmint ikjam question?
VAoSnE
No.156523
>>156521
CAT
xXwe1a
No.156525
xXwe1a
No.156536
>>156530
You are taking out candies one by one from a jar that has 1010 red candies, 2020 blue candies, and 3030 green candies in it. What is the probability that there is at least 11 blue candy and 11 green candy left in the jar when you have taken out all the red candies?
Assume that the candies of the same color are indistinguishable from one another.
4rWRjk
No.156574
>>156536
0.582 something something? I am in car sirs its difficult to calculate.
wklwIe
No.156824
This thread made me realise that I'm dumb
